Filters
Question type

Study Flashcards

In the accompanying figure, the chance that individual III- 5 is a heterozygous carrier is _________ . In the accompanying figure, the chance that individual III- 5 is a heterozygous carrier is _________ .   A)  25% B)  75% C)  100% D)  0% E)  50%


A) 25%
B) 75%
C) 100%
D) 0%
E) 50%

F) B) and E)
G) C) and D)

Correct Answer

verifed

verified

A ratio of 9:3:3:1 is expected among the F2 progeny of a dihybrid cross as a result of___________of alleles at two loci.

Correct Answer

verifed

verified

independen...

View Answer

The P value is a quantitative expression of the probability that the results of another experiment of the same size and structure will DEVIATE FROM EXPECTED RESULTS AS MUCH AS OR MORE THAN BY CHANCE. The greater the difference between observed and expected results of an experiment,_________ .


A) the lower the ç2 value and the lower the P value
B) the lower the ç2 value and the greater the P value
C) the greater the ç2 value; but the P value is unaffected
D) the greater the ç2 value and the greater the P value
E) the greater the ç2 value and the lower the P value

F) B) and D)
G) B) and E)

Correct Answer

verifed

verified

The gene L determines hair length in rabbits. The gene B determines hair color. A rabbit with long, black hair is crossed to a rabbit with short, white hair. All the offspring have long, black hair. What are the genotypes of the parents?


A) LLBB × llbb
B) Llbb × llBb
C) LlBb × LlBb
D) LlBb × llbb
E) Impossible to determine from the information given

F) B) and C)
G) None of the above

Correct Answer

verifed

verified

Tim and Mary are planning to start a familiy. While neither of them have cystic fibrosis, a rare autosomal recessi disease, they are concerned that their children could have the disease since Tim's father, John, AND Mary's broth Ralph both have the disease. a. Draw a pedigree of the inheritance of the cystic fibrosis allele in this family. b. On your pedigree, indicate any individuals that must be carriers. c. What is the probability that Tim will be a carrier for the disease allele? d. What is the probability that Mary will be a carrier for the disease allele? e. What is the probability that Tim and Mary will have a child with the disease?

Correct Answer

verifed

verified

a.
blured image b.
blured image ...

View Answer

In mice, black coat color is dominant to white coat color. In the pedigree below, mice with a black coat are represented by darkened symbols, and those with white coats are shown as open symbols. In mice, black coat color is dominant to white coat color. In the pedigree below, mice with a black coat are represented by darkened symbols, and those with white coats are shown as open symbols.   What is the genotype of III- 1? A)  heterozygous or homozygous recessive B)  heterozygous C)  homozygous recessive D)  homozygous dominant E)  homozygous dominant or heterozygous What is the genotype of III- 1?


A) heterozygous or homozygous recessive
B) heterozygous
C) homozygous recessive
D) homozygous dominant
E) homozygous dominant or heterozygous

F) All of the above
G) A) and B)

Correct Answer

verifed

verified

A couple has four children. What is the probability that they have four boys?


A) 1/2
B) 1/16
C) 1/4
D) 1/32
E) 1/8

F) A) and E)
G) B) and D)

Correct Answer

verifed

verified

In 1997, a gene called Le was discovered by two research groups led by David Martin and Diane Lester. Allelic variation in the Le gene, which controls elongation of the plant stem between branches, is responsible for which trait in peas?


A) yellow and green pod color
B) inflated and constricted pod shape
C) axial and terminal flower position
D) tall and short plant height
E) purple and white flowers

F) B) and E)
G) A) and E)

Correct Answer

verifed

verified

In peas, axial (A) flower position is dominant to terminal (a) , tall (L) is dominant to short (l) , and yellow (Y) is dominant to green (y) . If a plant that is heterozygous for all three traits is allowed to self- fertilize, how many of the offspring would show the dominant phenotype for all three traits?


A) 3/64
B) 32/64
C) 27/64
D) 9/64
E) 64/64

F) A) and D)
G) D) and E)

Correct Answer

verifed

verified

What genotypic ratio would you expect to observe among the progeny of a monohybrid cross?


A) 3:1
B) 1:2:1
C) 1:3:2:1
D) 1:3
E) 9:3:3:1

F) C) and E)
G) A) and B)

Correct Answer

verifed

verified

The law of independent assortment predicts that crossing of dihybrid F1 plants to one another would produce nine genotypes in a _______ ratio among F2 progeny.

Correct Answer

verifed

verified

What is the probability of rolling one six- sided die and obtaining a 1 or a 2?

Correct Answer

verifed

verified

1/6 + 1/6 ...

View Answer

A geneticist is investigating the inheritance of two autosomal recessive genes in mice, one for obesity (LEP) and another for autism (oprm1). The table below provides the number of offspring observed, for each phenotype, when dihybrid mice are testcrossed:  Phenotype  Observed(O)  Expected (E)OE(OE)2(OE)2/E wild- type 88 obese 68 autistic 64 obese, autistic 80(OE)2/E=\begin{array} { | l | c | l | l | l | l | } \hline \text { Phenotype } & \text { Observed(O) } & \text { Expected } ( \mathrm { E } ) & \mathrm { O } - \mathrm { E } & ( \mathrm { O } - \mathrm { E } ) 2 & ( \mathrm { O } - \mathrm { E } ) 2 / \mathrm { E } \\\hline \text { wild- type } & 88 & & & & \\\hline \text { obese } & 68 & & & & \\\hline \text { autistic } & 64 & & & & \\\hline \text { obese, autistic } & 80 & & & & \\\hline & & & & & \sum ( \mathrm { O } - \mathrm { E } ) ^ { 2 } / \mathrm { E } = \\\hline\end{array} Fill in the table above and determine: a. the chi- square (χ²) value (to the nearest hundredth) for the chance hypothesis that the two genes assort independently b. the degrees of freedom c. whether or not you would reject your chance hypothesis that the two genes assort independently, based on approximate P value, and the justification for why

Correct Answer

verifed

verified

blured image blured image a. 4.85
b. 3
c. You would fail to reje...

View Answer

In the accompanying figure, the chance that individual IV- 7 is a heterozygous carrier is __________ . In the accompanying figure, the chance that individual IV- 7 is a heterozygous carrier is __________ .   A)  2/3 B)  1/2 C)  1/3 D)  1/4 E)  3/4


A) 2/3
B) 1/2
C) 1/3
D) 1/4
E) 3/4

F) None of the above
G) D) and E)

Correct Answer

verifed

verified

A geneticist is investigating the inheritance of two autosomal recessive genes in mice, one for obesity (LEP) and for autism (oprm1). The table below provides the number of offspring observed, for each phenotype, when dihy mice are crossed:  Phenotype  Observed(O)  Expected (E)  O- E (OE)2(OE)2/E wild- type 154 obese 69 autistic 58 obese, autistic 23(OE)2/E=\begin{array} { | l | c | l | l | l | l | } \hline \text { Phenotype } & \text { Observed(O) } & \text { Expected (E) } & \text { O- E } & ( \mathrm { O } - \mathrm { E } ) 2 & ( \mathrm { O } - \mathrm { E } ) 2 / \mathrm { E } \\\hline \text { wild- type } & 154 & & & & \\\hline \text { obese } & 69 & & & & \\\hline \text { autistic } & 58 & & & & \\\hline \text { obese, autistic } & 23 & & & & \\\hline & & & & & \sum ( \mathrm { O } - \mathrm { E } ) ^ { 2 } / \mathrm { E } = \\\hline\end{array} Fill in the table above and determine: a. the chi- square (χ²) value (to the nearest hundredth) for the chance hypothesis that the two genes assort independently b. the degrees of freedom c. whether or not you would reject your chance hypothesis that the two genes assort independently, based on y approximate P value, and the justification for why

Correct Answer

verifed

verified

blured image blured image a. 5.08
b. 3
c. You would fail to reje...

View Answer

Huntington's disease is an autosomal dominant trait. Given the pedigree below, if individual IV- 2 has three children with a normal man, what is probability that exactly two of the three children would have the disorder? Huntington's disease is an autosomal dominant trait. Given the pedigree below, if individual IV- 2 has three children with a normal man, what is probability that exactly two of the three children would have the disorder?   A)  3/8 B)  7/8 C)  0 D)  1/2 E)  1/8


A) 3/8
B) 7/8
C) 0
D) 1/2
E) 1/8

F) D) and E)
G) A) and D)

Correct Answer

verifed

verified

In peas, the yellow allele is dominant over the green allele. A plant with yellow peas was crossed to a plant with green peas. The resulting plants were 50% yellow and 50% green. What are the genotypes of the parents in this cross?


A) yy × yy
B) Yy × yy
C) YY × yy
D) Yy × Yy
E) YY × Yy

F) B) and C)
G) B) and D)

Correct Answer

verifed

verified

In a test cross, a pure- breeding plant is crossed with a plant suspected to be heterozygous (Aa). What is the genotype of the pure- breeding plant?

Correct Answer

verifed

verified

The pedigree suggests which mode of inheritance for an allele on chromosome 15? The pedigree suggests which mode of inheritance for an allele on chromosome 15?

Correct Answer

verifed

verified

autosomal ...

View Answer

The P value is dependent on the number of _______, which is equal to the number of independent variables in an experiment.

Correct Answer

verifed

verified

degrees of...

View Answer

Showing 21 - 40 of 55

Related Exams

Show Answer