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Hemophilia (h) is a sex-linked recessive trait.If a hemophiliac male marries a carrier female,


A) 50% of their daughters will be hemophiliac.
B) 75% of their daughters will be hemophiliac.
C) 25% of their daughters will be hemophiliac.
D) 25% of their sons will be hemophiliac.
E) 75% of their sons will be hemophiliac.

F) B) and D)
G) A) and B)

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Which of the following sex-linked disorders is characterized by an abnormal number of repeat sequences in the genome?


A) fragile X syndrome
B) hemophilia
C) color-blindness
D) Duchenne muscular dystrophy
E) None of the answer choices is true.

F) All of the above
G) None of the above

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A person with an XO genotype is classified as having


A) Down syndrome.
B) cri du chat syndrome.
C) Turner syndrome.
D) Klinefelter syndrome.
E) a poly-X state.

F) None of the above
G) A) and B)

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Which refers to the loss of a portion of a chromosome?


A) inversion
B) translocation
C) deletion
D) duplication
E) monosomy

F) A) and C)
G) A) and B)

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Which of the following sex-linked diseases is characterized by the absence of a clotting factor?


A) hemophilia
B) fragile X syndrome
C) color-blindness
D) Duchenne muscular dystrophy
E) None of the answer choices is true.

F) A) and E)
G) A) and D)

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If a chromosomal segment is turned around 180 Β°\degree ,the chromosomal mutation is termed a(n)


A) translocation.
B) duplication.
C) deletion.
D) inversion.
E) monosomy.

F) All of the above
G) A) and D)

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A female with two Barr bodies in her cells would have what combination of sex chromosomes?


A) XXY
B) XXXY
C) XXX
D) XX
E) XYY

F) A) and C)
G) A) and B)

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C

If an individual has a XYY genotype,they are classified as having


A) Down syndrome.
B) cri du chat syndrome.
C) Turner syndrome.
D) Klinefelter syndrome.
E) Jacobs syndrome.

F) A) and B)
G) B) and D)

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When homologous chromosomes fail to separate during meiosis,this is termed


A) linked genes.
B) disjunction.
C) nondisjunction.
D) crossover.
E) monosomy.

F) C) and D)
G) D) and E)

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A karyotype will NOT reveal which of the following genetic diseases?


A) Turner syndrome
B) Klinefelter syndrome
C) Down syndrome
D) cri du chat syndrome
E) hemophilia

F) B) and C)
G) B) and E)

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A normal male marries a color-blind woman.What percent of their female children will be color-blind?


A) 0%
B) 25%
C) 50%
D) 75%
E) 100%

F) None of the above
G) A) and B)

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If a person inherits two X chromosomes,this individual will be


A) female.
B) male.
C) color-blind.
D) sterile.
E) a poly-X female.

F) A) and B)
G) A) and C)

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Down syndrome


A) is due to disjunction of chromosomes.
B) individuals have two number 21 chromosomes.
C) may occur at a lower rate in women over 40.
D) can occur if the sperm has an extra number 21 chromosome.
E) persons have normal-appearing eyelids.

F) B) and D)
G) All of the above

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D

Which statement is NOT true about Down syndrome?


A) It is caused by a third copy of chromosome 21.
B) Greatly increased incidence occurs with fathers over age 40.
C) It is usually associated with chromosomal nondisjunction in meiosis.
D) Characteristics include mental retardation and extra eyelid folds.
E) Affected individuals display mental retardation.

F) A) and D)
G) C) and D)

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B

Which refers to the movement of a piece of one chromosome to another nonhomologous chromosome?


A) inversion
B) translocation
C) deletion
D) duplication
E) monosomy

F) B) and E)
G) B) and D)

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A person who has an extra copy of a chromosome is said to have


A) monosomy.
B) bisomy.
C) trisomy.
D) nondisjunction.
E) duplication.

F) B) and C)
G) A) and E)

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An XXX female would most likely result from nondisjunction in


A) the mother during egg formation.
B) the father during sperm formation.
C) in both the mother and father during gamete formation.
D) the fertilized egg.
E) neither the mother nor the father.

F) A) and B)
G) A) and C)

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If a woman is a carrier for the color-blind recessive allele and her husband has normal vision,what are their chances that a son will be color-blind?


A) None,because the father is normal.
B) 50%,since the mother is only a carrier.
C) 100% because the mother has the gene.
D) 25% because the mother is a hybrid.
E) None since the son will also be just a carrier.

F) A) and B)
G) B) and D)

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Generally,it is not possible to determine whether nondisjunction failed to occur in oogenesis or spermatogenesis.However,it is possible to assert that _____ resulted in nondisjunction in ____.


A) XXY; oogenesis
B) XYY; spermatogenesis
C) XXX; oogenesis
D) XXY; spermatogenesis
E) XO; oogenesis

F) C) and E)
G) A) and B)

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Considering that males can have Klinefelter (XXY) syndrome,XYY,and normal XY chromosomal combinations,and females can have Turner (XO) syndrome,poly-X (XXX,XXXX) ,and normal XX combinations,it is obvious that


A) maleness results from the presence of only one X chromosome.
B) maleness results from the absence of two or more X chromosomes.
C) maleness results from the minimal presence of one Y chromosome.
D) femaleness results from the presence of two or more X chromosomes.
E) sex determination is a delicate balance between X and Y chromosomes.

F) B) and C)
G) A) and B)

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